In the given circuit diagram,the currents $I_1 = -0.3\,A$,$I_4 = 0.8\,A$ and $I_5 = 0.4\,A$ are flowing as shown. The currents $I_2, I_3$ and $I_6$ respectively are

The Wheatstone bridge shown in the figure gets balanced when the carbon resistor used as $R_1$ has the colour code (Orange,Red,Brown). The resistors $R_2$ and $R_4$ are $80 \, \Omega$ and $40 \, \Omega$,respectively. Assuming that the colour code for the carbon resistors gives their accurate values,the colour code for the carbon resistor used as $R_3$ would be

In the circuit shown,$E_1 = 4.0 \ V, R_1 = 2 \ \Omega, E_2 = 6.0 \ V, R_2 = 4 \ \Omega$ and $R_3 = 2 \ \Omega$. The current $I_1$ is : ................ $A$

The current through the branch $BD$ in the given circuit is: (in $\,A$)

If the potential difference between $B$ and $D$ is zero,the value of $x$ is $\frac{1}{n} \Omega$. The value of $n$ is .......

In the given circuit,if the potential at point $B$ is $24 \ V$,the potential at point $A$ is: (in $V$)